0=10x^2-12x-16

Solution for 0=10x^2-12x-16 equation:

0=10x^2-12x-16

We move all terms to the left:

0-(10x^2-12x-16)=0

We add all the numbers together, and all the variables

-(10x^2-12x-16)=0

We get rid of parentheses

-10x^2+12x+16=0

a = -10; b = 12; c = +16;
Δ = b2-4ac
Δ = 122-4·(-10)·16
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-28}{2*-10}=\frac{-40}{-20}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+28}{2*-10}=\frac{16}{-20}
=-4/5
$